Question 890: The permeter of a rectangle is 32 ft. The length is 6ft 5in. Find the width. Find the area in inches. Found 3 solutions by KMST, math_tutor2020, MathTherapy:Answer by KMST(5484) (Show Source):
You can put this solution on YOUR website! The perimeter of a rectangle can be calculated as ,
where and .
Let's convert everything into inches.
In inches, 32 feet is , and 6ft 5in is .
If a rectangle with a perimeter of has a pair of parallel sides of length and another pair of parallel sides of length , in inches, --> --> --> --> -->
The area of the rectangle in square inches is square inches.
The first task is to convert all the given info to inches only.
Because 1 foot = 12 inches, multiply both sides by 32 to find that 32 feet = 384 inches.
Similarly 6 feet = 6*12 = 72 inches.
So,
length = 6 ft + 5 in = 72 in + 5 in = 77 in
L = length = 77 inches
W = width = unknown for now
P = perimeter of a rectangle = 384 inches
P = 2L + 2W = 384
2L + 2W = 384
2*77 + 2W = 384
154 + 2W = 384
2W = 384-154
2W = 230
W = 230/2
W = 115 inches is the width
If you need it in "feet + inches", then,
115/12 = 9 remainder 7 = 9 feet + 7 inches
The plus sign between the entities can be replaced with "and" or the ampersand symbol. Or you can erase the plus sign.
Lastly:
area = length*width
area = (77 inches)*(115 inches)
area = 8855 square inches
The permeter of a rectangle is 32 ft. The length is 6ft 5in. Find the width. Find the area in inches.
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Perimeter: 32'
Length: 6' 5"
Perimeter: 2L + 2W = 32
2(L + W) = 2(16)
L + W = 16
6' 5" + W = 16 ---- Substituting 6' 5" for L
W, or width = 16' - 6' 5", or 15' 12" - 6' 5" = 9' 7"
Area: LW = (6' 5")(9' 7") = (72 + 5)"(108 + 7)" = (77")(115") = 8,855 sq inches
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