SOLUTION: The area of a rectangle is 66m^2, and the length of the rectangle is 1m more than double the width. Find the dimensions of the rectangle.

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Question 877931: The area of a rectangle is 66m^2, and the length of the rectangle is 1m more than double the width. Find the dimensions of the rectangle.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a rectangle is A square meters , and the length of the rectangle is k more than m times the width. Find the dimensions of the rectangle.

Let w = width
Let L = length
Later, let k=1 and m=2.

Description gives L=mw%2Bk, and wL=A.
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w%28mw%2Bk%29=A
mw%5E2%2Bkw=A
mw%5E2%2Bkw-A=0
You could do the numberic variable substitutions now in anticipation that the quadratic is factorable. Solve for w and use the result or the value to find L.
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2w%5E2%2Bw-66=0
Try for factorability,
%282w-11%29%28w%2B6%29=0
Use the solution 2w-11=0
2w=11
highlight%28w=11%2F2%29.
highlight%28L=12%29.