SOLUTION: The perimeter of a rectangle is 36m. If the width were doubled and the length were increased by 11m, the perimeter would be 68m. What are the length and width of the rectangle?

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Question 861399: The perimeter of a rectangle is 36m. If the width were doubled and the length were increased by 11m, the perimeter would be 68m. What are the length and width of the rectangle?
Answer by ben720(159) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter is 36m. 2l%2B2w=36
If the width were doubled and length increased by 8, p=68 2%28l%2B11%29%2B2%2A2w=68
2l%2B22%2B4w=68
2l%2B4w=46
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++2%5Cx+%2B+2%5Cy+=+36%2C%0D%0A++++2%5Cx+%2B+4%5Cy+=+46+%29%0D%0A++We'll use substitution. After moving 2*y to the right, we get:
2%2Ax+=+36+-+2%2Ay, or x+=+36%2F2+-+2%2Ay%2F2. Substitute that
into another equation:
2%2A%2836%2F2+-+2%2Ay%2F2%29+%2B+4%5Cy+=+46 and simplify: So, we know that y=5. Since x+=+36%2F2+-+2%2Ay%2F2, x=13.

Answer: system%28+x=13%2C+y=5+%29.