SOLUTION: the height of a triangle is 4 feet less than the base. The area of the triangle is 198 square feet. Fine the length of the base and the height of the triangle 1/2(x(x+4)=198

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Question 860504: the height of a triangle is 4 feet less than the base. The area of the triangle is 198 square feet. Fine the length of the base and the height of the triangle

1/2(x(x+4)=198
1/2(x^2+4)=198
x^2+4x-396
I don't know whats next

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Question States***height of a triangle is 4 feet less than the base
1/2(x(x-4)=198
1/2(x^2-4x)=198
x^2-4x-396 = 0 |Hint: sqrt(396) = ~19.9 (2*8) ends in 6
(x -22)(x+18) = 0 (Tossing out the negative solution for unit measure)
x = 22ft, the width. Then length is 18ft
Or quadratic Eq always works
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-4x%2B-396+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-4%29%5E2-4%2A1%2A-396=1600.

Discriminant d=1600 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--4%2B-sqrt%28+1600+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-4%29%2Bsqrt%28+1600+%29%29%2F2%5C1+=+22
x%5B2%5D+=+%28-%28-4%29-sqrt%28+1600+%29%29%2F2%5C1+=+-18

Quadratic expression 1x%5E2%2B-4x%2B-396 can be factored:
1x%5E2%2B-4x%2B-396+=+1%28x-22%29%2A%28x--18%29
Again, the answer is: 22, -18. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-4%2Ax%2B-396+%29