SOLUTION: All verticle of rombus lie on circle find the area of rombus if area of circle is 2464 cm2
Let us start with some basic facts:
1. A rhombus inscribed in a circle must be a squ
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Let us start with some basic facts:
1. A rhombus inscribed in a circle must be a squ
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Question 830912: All verticle of rombus lie on circle find the area of rombus if area of circle is 2464 cm2
Let us start with some basic facts:
1. A rhombus inscribed in a circle must be a square, with its diagonals passing through the center of the circle (If you want proof for this I will go into that later, but I don't want to detract from the problem at hand)
2. Since the area of the circle is 2464, the radius must be the square root of 2464/PI, i.e. 28 centimeters.
3. That means the diameter of the circle is 56 centimeters.
4. Now consider either half of this rhombus (square). It is a right-angled triangle with the two minor sides each equal to x (unknown) and hypotenuse equal to 56.
5. Apply Pythagoras: x-squared + x-squared = 56-squared. That is, 2 times x-squared = 56-squared. So x-squared = 28 times 56 = 1568
6. The area of the rhombus (square) is therefore 1568 square cm Answer by Elomeht(22) (Show Source):
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