Question 820460: a ball is thrown straight upward at an initial speed of 240 feet per second. From physics, we know that the ball will reach a height of h feet after t seconds where h and t are related by the following formula: h=-16t^2+240t. when did the ball hit the ground?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! h = -16t^2 + 240t
---
the above quadratic equation is in standard form, with a=-16, b=240, and c=0
---
to solve the quadratic equation, by using the quadratic formula, plug this:
-16 240 0
into this: https://sooeet.com/math/quadratic-equation-solver.php
---
the two real roots (i.e. the two x-intercepts), of the quadratic are:
t = 0
t = 15
---
answer:
ball hits the ground 15 seconds after being thrown
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
|
|
|
