SOLUTION: The number of diagonals of a polygon is 275. How many sides are there?

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Question 766550: The number of diagonals of a polygon is 275. How many sides are there?
Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!

Number of diagonals of a polygon of n sides is given by the formula

n*(n-3)/2  where n >= 3

(I'm not giving the proof for this formula here - it has already been described
as part of other solutions in this site)

Here since it is given that the polygon has 275 diagonals

n%2A%28n-3%29%2F2+=+275 or n%2A%28n-3%29+=+550

n%5E2+-+3%2An+-+550+=+0 which is a standard quadratic equation.

Solving this by factorization

n%5E2+-+25%2An+%2B+22%2An+-+550+=+0

n%2A%28n+-+25%29+%2B+22%2A%28n+-+25%29+=+0

%28n+-+25%29%2A%28n+%2B+22%29+=+0

Solving, n = 25 or n = -22

Since n cannot be negative, the polygon has highlight%2825%29 sides.

:)