SOLUTION: If Susie stands 50 feet away from a building, how tall is the building if a 100 ft ladder reaches from the ground where Susie is standing to the top of the building? (Round to the
Algebra ->
Customizable Word Problem Solvers
-> Geometry
-> SOLUTION: If Susie stands 50 feet away from a building, how tall is the building if a 100 ft ladder reaches from the ground where Susie is standing to the top of the building? (Round to the
Log On
Question 759531: If Susie stands 50 feet away from a building, how tall is the building if a 100 ft ladder reaches from the ground where Susie is standing to the top of the building? (Round to the nearest hundredth) Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Pythagoras
A right angled triangle with base = 50ft
and the hypotenuse = 100ft
To find the height of the building:
100^2 - 50^2 = Height^2
7500 = Height^2
height = square root of 7500
height = 86.6 feet. (86.603)
Hope this helps.
:-)
