Question 733622: half the perimeter of a rectangular lot, which is 50 feet longer than it is wide, is 350 feet. what are the dimensions of the lot?
Answer by chana(69)   (Show Source):
You can put this solution on YOUR website! Perimeter of the rectangle = 2L+2B
L=B+50
half the perimeter of a rectangular lot, which is 50 feet longer than it is wide, is 350 feet
So,
.5*(2* (B+50))+(2B))= 350
4B+100=700
solving for B we get, B as 150 feet
And L= 150+50
=200 feet
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