SOLUTION: Three sides of a right triangle are labeled as x-2, x+5 and x+6. I need to find X. I used the Pythagorean theorem and after all my calculations I came to x=6. However, when I pu

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: Three sides of a right triangle are labeled as x-2, x+5 and x+6. I need to find X. I used the Pythagorean theorem and after all my calculations I came to x=6. However, when I pu      Log On

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Question 722403: Three sides of a right triangle are labeled as x-2, x+5 and x+6. I need to find X. I used the Pythagorean theorem and after all my calculations I came to x=6. However, when I put it back into the theorem it does not add up. I am concerned I am doing something wrong in the algebra part of this equation. Can you help?
Here is my formula: +%28x-2%29squared+%2B+%28x%2B5%29squared+=+%28x%2B6%29+squared+

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
I continue
%28x-2%29%5E2%2B%28x%2B5%29%5E2=%28x%2B6%29%5E2

x%5E2-4x%2B4%2Bx%5E2%2B10x%2B25=+x%5E2%2B12x%2B36

x%5E2-6x-7=0

x%5E2-7x%2Bx-7=0
x%28x-7%29%2B1%28x-7%29=0
(x-7)(x+1)=0
x= 7 Taking the positive value
Check
5^2+12^2
25+144=169