SOLUTION: what is the area and perimiter of a rectangle with the 52 length and width 23

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Question 722148: what is the area and perimiter of a rectangle with the 52 length and width 23
Answer by Alan3354(69443) About Me  (Show Source):
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what is the area and perimiter of a rectangle with the 52 length and width 23
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Area = L*W
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Perimeter = 2L + 2W