SOLUTION: what is the answer to 10x exponent 2 - 9x + 6 its dealing with factoring trinomials: ax exponent 2 + bx + c.

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Question 720960: what is the answer to 10x exponent 2 - 9x + 6 its dealing with factoring trinomials: ax exponent 2 + bx + c.
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

10x%5E2+-9x+%2B+6
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression 10x%5E2-9x%2B6, we can see that the first coefficient is 10, the second coefficient is -9, and the last term is 6.



Now multiply the first coefficient 10 by the last term 6 to get %2810%29%286%29=60.



Now the question is: what two whole numbers multiply to 60 (the previous product) and add to the second coefficient -9?



To find these two numbers, we need to list all of the factors of 60 (the previous product).



Factors of 60:

1,2,3,4,5,6,10,12,15,20,30,60

-1,-2,-3,-4,-5,-6,-10,-12,-15,-20,-30,-60



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to 60.

1*60 = 60
2*30 = 60
3*20 = 60
4*15 = 60
5*12 = 60
6*10 = 60
(-1)*(-60) = 60
(-2)*(-30) = 60
(-3)*(-20) = 60
(-4)*(-15) = 60
(-5)*(-12) = 60
(-6)*(-10) = 60


Now let's add up each pair of factors to see if one pair adds to the middle coefficient -9:



First NumberSecond NumberSum
1601+60=61
2302+30=32
3203+20=23
4154+15=19
5125+12=17
6106+10=16
-1-60-1+(-60)=-61
-2-30-2+(-30)=-32
-3-20-3+(-20)=-23
-4-15-4+(-15)=-19
-5-12-5+(-12)=-17
-6-10-6+(-10)=-16




From the table, we can see that there are no pairs of numbers which add to -9. So 10x%5E2-9x%2B6 cannot be factored.



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Answer:



So 10%2Ax%5E2-9%2Ax%2B6 doesn't factor at all (over the rational numbers).



So 10%2Ax%5E2-9%2Ax%2B6 is prime.