SOLUTION: The width of a rectangle is 7 cm less than its length and its area is 250cm. Find its dimmensions*you may use any method. so what I tried doing is let X represent the length and

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: The width of a rectangle is 7 cm less than its length and its area is 250cm. Find its dimmensions*you may use any method. so what I tried doing is let X represent the length and      Log On

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Question 691394: The width of a rectangle is 7 cm less than its length and its area is 250cm. Find its dimmensions*you may use any method.
so what I tried doing is let X represent the length and do 250 equals (x-7)*7 but I feel like this is super wrong. Please help. Thanks in advance

Answer by mouk(232) About Me  (Show Source):
You can put this solution on YOUR website!
Nearly correct !
Let length=+x+, then width=x-7
Area = 250 so +x+%28x-7%29+=+250+, Expanding gives:
+x%5E2+-+7x+=+250+
+x%5E2+-+7x+-+250+=+0+
Solving using the quadratic formula gives:
x+=+%287+%2B-+sqrt%28+49%2B1000+%29%29%2F%282%29+
x+=+-12.69+ or x+=+19.69+ (working to 2dp)
Obviously as x is the length then x+%3E0+ so solution is x+=+19.69+