SOLUTION: the perimeter of a lot is 190 m. the width is one fourth the length. find the dimensions.

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Question 657819: the perimeter of a lot is 190 m. the width is one fourth the length. find the dimensions.
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
given:
the perimeter of a lot is P=190m
the width W is 1%2F4 the length L:

W=%281%2F4%29L

P=2L%2B2W....substitute L

190m=2L%2B2%28%281%2F4%29L%29

190m=2L%2Bcross%282%29%28%281%2Fcross%284%292%29L%29

190m=2L%2B%281%2F2%29L

190m=%284%2F2%29L%2B%281%2F2%29L

190m=%285%2F2%29L

190m%2A2=5L

380m%2F5=L

highlight%2876m=L%29
W=%281%2F4%29L
W=%281%2F4%2976m
W=highlight%2819m%29