SOLUTION: There is a pool with a cement walkway around it. The pool measures 6 meters by 10 meters and the total area of the pool is 96 meters. Find the width of the walkway

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Question 624813: There is a pool with a cement walkway around it. The pool measures 6 meters by 10 meters and the total area of the pool is 96 meters. Find the width of the walkway
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
There is a pool with a cement walkway around it. The pool measures 6 meters by 10 meters and the total area of the pool is 96 meters. Find the width of the walkway
.
Let w = width of walkway
then
"area of pool & walkway" - "area of pool" = 96
(6+2w)(10+2w) - (6)(10) = 96
60+12w+20w+4w^2 - 60 = 96
60+32w+4w^2 - 60 = 96
32w+4w^2 = 96
4w^2+32w = 96
4w^2+32w-96 = 0
w^2+8w-24 = 0
applying the quadratic formula yields:
w = {-10.32, 2.32}
we can throw out the negative solution leaving:
w = 2.32 meters
.
Details of quadratic follows:
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation aw%5E2%2Bbw%2Bc=0 (in our case 1w%5E2%2B8w%2B-24+=+0) has the following solutons:

w%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%288%29%5E2-4%2A1%2A-24=160.

Discriminant d=160 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-8%2B-sqrt%28+160+%29%29%2F2%5Ca.

w%5B1%5D+=+%28-%288%29%2Bsqrt%28+160+%29%29%2F2%5C1+=+2.32455532033676
w%5B2%5D+=+%28-%288%29-sqrt%28+160+%29%29%2F2%5C1+=+-10.3245553203368

Quadratic expression 1w%5E2%2B8w%2B-24 can be factored:
1w%5E2%2B8w%2B-24+=+1%28w-2.32455532033676%29%2A%28w--10.3245553203368%29
Again, the answer is: 2.32455532033676, -10.3245553203368. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B8%2Ax%2B-24+%29