SOLUTION: a piece of wire 14 cm long is cut into two pieces. one piece is used to form a square shape and the other to form a rectangle shape of which the length is twice its width. find the

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Question 621931: a piece of wire 14 cm long is cut into two pieces. one piece is used to form a square shape and the other to form a rectangle shape of which the length is twice its width. find the length of the side of the square if the combined area of the two shapes is 5.35cm^2.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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a piece of wire 14 cm long is cut into two pieces.
one piece is used to form a square shape and
the other to form a rectangle shape of which the length is twice its width.
find the length of the side of the square if the combined area of the two shapes is 5.35cm^2
;
Let x = the width of the rectangle
then
2x = the length of the rectangle
:
Let y = the side of the square
then
he perimeter of the rectangle: 2(2x) + 2x = 6x
The perimeter of the squares = 4y
therefore
6x + 4y = 14
Simplify, divide by 2
3x + 2y = 7
y = %287-3x%29%2F2
:
The area
2x^2 + y^2 = 5.35
y = sqrt%285.35-2x%5E2%29
:
Plot these two equations, you can see there is no intersection, so no solution as the problem is written
+graph%28+300%2C+200%2C+-1%2C+3%2C+-1%2C+3%2C+sqrt%285.35-2x%5E2%29%2C+%287-3x%29%2F2%29+