SOLUTION: In triangle ABC, segment AB is greater than segment BC, angle C measures = 4x-4 and angle A measures = x + 9. Find the minimum integral value of X.

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Question 618983: In triangle ABC, segment AB is greater than segment BC, angle C measures = 4x-4 and angle A measures = x + 9. Find the minimum integral value of X.
Answer by MathTherapy(10552) About Me  (Show Source):
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In triangle ABC, segment AB is greater than segment BC, angle C measures = 4x-4 and angle A measures = x + 9. Find the minimum integral value of X.

Since segment AB > segment BC, then angle C > angle A

Now, since angle C = 4x - 4, and angle A = x + 9, then:

4x - 4 > x + 9

4x - x > 9 + 4

3x > 13

x > 13%2F3, or 4%261%2F3, and therefore, the minimal integral value > 4%261%2F3 is highlight_green%285%29

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