SOLUTION: please help me solve this problem The length of a rectangle is five times more than the width. The perimeter is 36 in. What are the length and width of the rectangle?

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: please help me solve this problem The length of a rectangle is five times more than the width. The perimeter is 36 in. What are the length and width of the rectangle?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 615498: please help me solve this problem
The length of a rectangle is five times more than the width. The perimeter is 36 in. What are the length and width of the rectangle?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Hint:

"The length of a rectangle is five times more than the width" means L = 5W

"The perimeter is 36 in" means P = 36

Recall that the perimeter of a rectangle is P = 2L + 2W

So

P = 2L + 2W

36 = 2(5W) + 2W