SOLUTION: the length of rectangle is 14 feet more than the width. the perimeter of the rectangle is 132 feet. Find the width

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Question 600987: the length of rectangle is 14 feet more than the width. the perimeter of the rectangle is 132 feet. Find the width
Answer by godsgirls(5) About Me  (Show Source):
You can put this solution on YOUR website!
the length of rectangle is 14 feet more than the width. the perimeter of the rectangle is 132 feet. Find the width
First steps first: write equation A to model your problem.
perimeter = 2lengths + 2widths
p+=+2L+%2B+2W
your perimeter equals 132 ft. Therefore, equation A is: 132+=+2L+%2B+2W
We know that the length is 14 ft more than the width. Write equation B to model this:
Eliminate your parenthesis by multiplying: 132+=+2W+%2B+28+%2B+2W
Simplify: 132+=+4W+%2B+28
Isolate the variable (4W) by subtracting 28 from both sides: 104+=+4W
divide both sides by 4 to determine the value of w: 104%2F4+=+4W%2F4
simplify: 26+=+W
Your width is 26 ft. If you want to find the length, which you didn't ask for, add 14 to 26 to find the length ( 40 ft.)
I hope this helps!