You can put this solution on YOUR website! perimeter of a square is numerically greater than its area by 4. find its diagonal.
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Let s = the length of a side
The perimeter = 4s and the area = s^2
Given: perimeter is 4 more than the area
4s = s^2 + 4
Solve for s:
s^2 - 4s + 4 = 0
(s-2)(s-2) = 0
This gives s = 2
The diagonal is s* =