SOLUTION: A picture of a sunset has a square frame that is 2 inches wide. The area of the picture is one-third of the total area of the picture and frame. What are the dimensions of the p

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Question 548378: A picture of a sunset has a square frame that is 2 inches wide. The area of the picture is one-third of the total area of the picture and frame. What are the dimensions of the picture to the nearest quarter of an inch? please show me the steps
Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
Draw this. It's a square inside a larger square. Call the lengths of the sides of the inner square, the picture, x. Call the lengths of the sides of the larger square (the square made by the frame) x+4 because the 2 inch frame adds 2 inches on each side to the smaller square.


Area of a square is s%5E2
For the smaller square that's x%5E2
For the larger square that's %28x%2B4%29%5E2+=+x%5E2+%2B+8x+%2B16
The problem indicates that the area of the small square is 1/3 the area of the large square. In other words, three times the area of the small square equals the area of the large square.


3x%5E2+=+x%5E2+%2B+8x+%2B+16
Move what's on the right to the left of the = by subtracting it from both sides.


2x%5E2+-+8x+-+16+=+0
Divide both sides by 2.
x%5E2+-+4x+-+8+=+0
Factor by using the quadratic formula %28-b+%2B-+sqrt%28b%5E2+-4ac%29%29%2F2a

That gives two possible answers:
x=2-2sqrt%283%29+%3C=+0 The length cannot be negative so discard that.
x=2%2B2sqrt%283%29+=+5.46+=+5.5
Round it to the nearest quarter inch, so .46 rounds up to .5.


Check if 3%2A5.5%5E2+=+9.5%5E2.
90.75+=+90.25 Yes, it's close enough given we had to round up to the nearest quarter inch.

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