SOLUTION: a man is planning to fence the front part of his property with posts 2m apart. Short of money he decides to make the posts 3 m apart and uses 3 posts less. how wide is the property
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Question 545824: a man is planning to fence the front part of his property with posts 2m apart. Short of money he decides to make the posts 3 m apart and uses 3 posts less. how wide is the property? Found 2 solutions by vleith, Edwin McCravy:Answer by vleith(2983) (Show Source):
You can put this solution on YOUR website! You will always need one more post then the number of sections in a fence. That is, for a single section you need 2 posts. For a two section fence, you will need 3 posts. Etc
So the length of the fence is the {{(NumberOfPosts -1) * (WidthOfSection)}}}
In this problem, the length of the fence does't cange. Only the number of posts and the width of the section. So
Let x be the number of posts in the 2m fence.
then
If the number of posts in a 2m section fence is 10, then the length of the fence is = m
Check your answer using the 3m values.
If x = 10, the 10-3 = 7 is the number of posts in a 3m section fence = m
There is 1 more post than there are sections of fence between the posts.
He was originally planning to have N posts and N-1 2m sections of fence
between the posts, like this:
| 2m | 2m | 2m | 2m | 2m | .... | 2m |
But short of money he decided to have N-3 posts and N-4 3m sections of
fence between the posts instead, like this:
| 3m | 3m | 3m | 3m | ... | 3m |
So (N-1)×2 = (N-4)×3
2(N-1) = 3(N-4)
2N - 2 = 3N - 12
-N = -10
N = 10
So he was going to have 10 posts and 9 2m sections of fence between
them, so his property is 9×2m = 18m wide.
To check: Instead he used 7 posts and 6 3m sections of fence between
them, so his property is 6×3m = 18m wide.
So both ways his property is 18m wide.
Edwin