SOLUTION: If the area of a trapezoid is 32 and base 1 is x + 6 and base 2 is x+2 and the height = x, how can i solve for x?

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: If the area of a trapezoid is 32 and base 1 is x + 6 and base 2 is x+2 and the height = x, how can i solve for x?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 526077: If the area of a trapezoid is 32 and base 1 is x + 6 and base 2 is x+2 and the height = x, how can i solve for x?
Answer by Maths68(1474) About Me  (Show Source):
You can put this solution on YOUR website!
Base 1 = x+1
Base 2 = x+2
Height = x
Area = 32
Area of a trapezoid = height * (sum of two bases)/2
32=x*(x+1+x+2)/2
32=x(2x+3)/2
32*2=2x^2+3x
64=2x^2+3x
2x^2+3x-64=0
a=2, b=3, c=-64
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-3+%2B-+sqrt%28+3%5E2-4%2A%282%29%28-64%29%29%29%2F%282%2A2%29+
x+=+%28-3+%2B-+sqrt%28521%29%29%2F4+
x+=+%28-3+%2B-+22.825%29%2F4%29+
x+=+%28-3+%2B+22.825%29%2F4%29+ or x+=+%28-3+-+22.825%29%2F4%29+
x+=+%2819.825%2F4%29+ or x+=+%28-+25.825%2F4%29+
x+=+%2819.825%2F4%29+ or x+=+%28-+25.825%2F4%29+
x+=+%284.96%29+ or x+=+-+6.46+(inadmissible)
x+=+4.96
Base 1 = x+1 = 4.96+1 = 5.96
Base 2 = x+2 = 4.96+2 = 7.96
Height = x = 4.96