SOLUTION: a square poster has sides measuring 2 feet less than the sides of a square sign. if the difference between their areas is 32 square feet, find the lengths of the sides of the poste
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Question 478282: a square poster has sides measuring 2 feet less than the sides of a square sign. if the difference between their areas is 32 square feet, find the lengths of the sides of the poster and the sign Answer by cleomenius(959) (Show Source):
You can put this solution on YOUR website! The area of the sign minus the area of the poster is given as 32 sq ft.
The equation will be:
(x + 2)^2 - x^2 = 32
x^2 + 4x + 4 - x^2 = 32
4x + 4 = 32
4x = 28
x = 7 ft, the side of the poster.
x + 2 = 9 ft, the size of the sign
Too check:
81 sq ft minus 49 sq ft = 32 sq ft.
Cleomenius.
