SOLUTION: Here is the problem: The area of a square is twice the area of a triangle. The base of the triangle is 2 less than the side of the square and the height of the triangle is twice

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Question 45990: Here is the problem:
The area of a square is twice the area of a triangle. The base of the triangle is 2 less than the side of the square and the height of the triangle is twice the side of the square. Find the side of the square. What equation using one variable would you use to find the side of the square? And how would you solve the equation? Thank you so much.
Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
Base of triangle = x-2
Height os triangle = 2x
Side of square = x
Area of triangle = ( base * height ) / 2
-->%28%28x-2%29%282x%29%29%2F2
-->%282x%5E2-4x%29%2F2
Area of square --> 2%28%282x%5E2-4x%29%2F2%29 or x%5E2
EQUATION:
x%5E2=%284x%5E2-8x%29%2F2
2x%5E2=4x%5E2-8x
2x%5E2-8x=0
x=4
Hence, the side of the square is 4 cm.
Paul.