Question 449831: a circle has a diameter with endpoints (5, -2) and (-13 -6) what are the coordinates of the center of the circle
Found 3 solutions by mananth, ikleyn, mccravyedwin: Answer by mananth(16949) (Show Source):
You can put this solution on YOUR website! If the coordinates of A and B are ( x1, y1) and ( x2, y2) respectively, then the midpoint, M, of AB is given by the following formula M =
(5,-2)(-13,-6)
x=(5-13 )/2,y=(-2-13)/2
x= -4,y= -7.5
Answer by ikleyn(53742) (Show Source): Answer by mccravyedwin(420) (Show Source):
You can put this solution on YOUR website! If the coordinates of A and B are ( x1, y1) and ( x2, y2) respectively, then the midpoint, M, of AB is given by the following formula M =
(5,-2)(-13,-6)
x=(5-13 )/2,y=(-2-13)/2
x= -4,y= -7.5
Correction to mananth(16949)'s solution. She used -13, which was x2
where she should have used -6, which was y2. So her corrected solution is
If the coordinates of A and B are ( x1, y1) and ( x2, y2) respectively, then the midpoint, M, of AB is given by the following formula M =
(5,-2)(-13,-6)
x=(5-13 )/2,y=(-2-6)/2
x= -4,y= -4
Edwin
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