Question 446465: The vertices of the triangle are A(6,1), B(6,7) and C(10,7) show that the triangle is right angled and find it's sides? Found 2 solutions by mananth, ikleyn:Answer by mananth(16949) (Show Source):
You can put this solution on YOUR website! x1 y1 x2 y2
d=
6 1 6 7
d(AB)=
d=
d=
d(AB)= 6.00
x1 y1 x2 y2
d(BC)=
10 7 6 7
d=
d=
d=
d(BC)= 4.00
----
x1 y1 x2 y2
d(CA)=
10 7 6 1
d=
d=
d=
d(CA)= 7.215
d(AB)^2+d(BC)^2= d(AC)^2 if it is a right triangle
6^2+4^2= 7.215^2
52=52
You can put this solution on YOUR website! .
The vertices of the triangle are A(6,1), B(6,7) and C(10,7) show that the triangle is right angled and find it's sides?
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It is so simple . . . - much simpler than you think.
The side AB is vertical line x = 6, since points A and B have the same x-coordinate 6.
The side BC is horizontal line y = 7, since points B and C have the same y-coordinate 7.
Therefore, triangle ABC is a right-angled triangle.
The length of side AB is the difference y-coordinates points A and B |7-1| = 6 units.
The length of side BC is the difference x-coordinates points B and C |10-6| = 4 units.
The hypotenuse AC has the length = = units.
At this point, the problem is solved completely: all questions are answered.
You do not need to make complicated reasoning or complicated calculations, as @mananth does.
This problem teaches you to retrieve out geometric information from coordinates
of given points in coordinate plane.