SOLUTION: A kite flying 20 ft. above the ground is attached to a string 80 ft. long. The string is being held by a person on the ground.if the kite fell vertically to the ground, how far aw
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Question 437230: A kite flying 20 ft. above the ground is attached to a string 80 ft. long. The string is being held by a person on the ground.if the kite fell vertically to the ground, how far away from the stake would the kite land? Found 3 solutions by mananth, ikleyn, greenestamps:Answer by mananth(16949) (Show Source):
You can put this solution on YOUR website! sin = vertical/hypotenuse
Sine = 20/80
Sine= 1/4 =15 deg
..
Cos = base/hyptenuse
Cos 15* 80 = base
0.9659*80= 77 feet ground distance (approx)
You can put this solution on YOUR website! .
A kite flying 20 ft. above the ground is attached to a string 80 ft. long.
The string is being held by a person on the ground. if the kite fell vertically to the ground,
how far away from the stake would the kite land?
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In his solution, @mananth uses this scheme
Find sin of the angle ---> find arcsin ---> find cos ---> find the horizontal distance.
The use of trigonometry to solve the problem is a bit excessive -- unless a solution using trigonometry is required....
The problem simply involves a right triangle with hypotenuse 80 and one leg 20. The answer to the question is the length of the other leg, which can be found using the Pythagorean Theorem.