SOLUTION: Christopher cuts a length of wire. He bends it to form a rectangle that is four times as long as it is wide. If he wants the rectangle to have an area of 100 square inches, what

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: Christopher cuts a length of wire. He bends it to form a rectangle that is four times as long as it is wide. If he wants the rectangle to have an area of 100 square inches, what       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 425677: Christopher cuts a length of wire. He bends it to form a rectangle that is four times as long as it is wide. If he wants the rectangle to have an area of 100 square inches, what should be the length of the original piece of wire?
Found 2 solutions by josmiceli, lwsshak3:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the length = 4x in.
Let the width = x in.
given:
+4x%2Ax+=+100 in2
+x%5E2+=+25+ in2
+x+=+5+
+4x+=+20+
The length of wire is +4x+%2B+4x+%2B+x+%2B+x+=+10x+
+10x+=+10%2A5
10%2A5+=+50
The wire is 50 in long

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Christopher cuts a length of wire. He bends it to form a rectangle that is four times as long as it is wide. If he wants the rectangle to have an area of 100 square inches, what should be the length of the original piece of wire?
..
let x=width of rectangle
then 4x=length of rectangle
then 2*(x+4x)=10x=length of original piece of wire.
..
area of rectangle=length*width=x*4x=100
4x^2=100
x^2=100/4=25
x=5
10x=50
ans:
length of original piece of wire=50 inches