Question 415244: what is the perimeter of a rectangular field if it is 528 and the length is 5 times longer than it is wide. Answer by htmentor(1343) (Show Source):
You can put this solution on YOUR website! Perimeter = the sum of all 4 sides
Since it is a rectangle sum = 2l + 2w, where l = length and w = width
Thus 2l + 2w = 528 (1)
l = 5w (2)
Substituting for l in (1) gives 2*5w + 2w = 528
Or 12w = 528
Solving for w gives w = 528/12 = 44
And therefore l = 5*44 = 220
Check: 2*220 + 2*44 = 440 + 88 = 528
