SOLUTION: express secX-SinXTanX as a single function of X.

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Question 391094: express secX-SinXTanX as a single function of X.
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
Write everything in terms of sin and cos:

1%2Fcos%28x%29+-+sin%28x%29%2Asin%28x%29%2Fcos%28x%29 Add the two fractions

%281+-+sin%5E2+%28x%29%29%2Fcos%28x%29 Since 1+-+sin%5E2+%28x%29+=+cos%5E2+%28x%29 by the Pythagorean identity, replace the numerator with cos%5E2+%28x%29 to obtain

cos%5E2+%28x%29%2Fcos+%28x%29 which is equal to cos+%28x%29 provided that cos+%28x%29+%3C%3E+0.