Draw three green radii (which are 1 inch long) to the vertices, label
the center of the circle O.
Extend AO down to intersect BC at point D
Triangle BDO is a 30°-60°-90° right triangle.
Therefore the red line OD is one half of green radius OB
So OB is 1 inch, and OD is
inch, so by the Pythagorean
theorem:
BDČ + ODČ = OBČ
BDČ + (
)Č = (1)Č
BDČ +
= 1
BDČ =
BD =
BD =
BD is one-half of BC, a side of eqilateral triangle ABC.
Therefore BC is
So each side of the equilateral triangle is
inches.
Edwin