SOLUTION: The perimeter of a rectangle is 56 in. the length is 5 less thean the width. Find the demensions.

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Question 38463This question is from textbook
: The perimeter of a rectangle is 56 in. the length is 5 less thean the width. Find the demensions. This question is from textbook

Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
The formula for perimeter is P = 2L + 2W
Let W be the width.
The length L is given in the problem as W - 5.
Now substitute
56 = 2(W - 5) + 2W
56 = 2W - 10 + 2W
56 = 4W - 10
66 = 4W
W = 66/4 = 33/2 = 16 1/2
L = W - 5 = 11 1/2