SOLUTION: I am haveing problems solving this problem I have tried numerous times but i just do not understand it. A rectangle is 5 times as long as it is wide. If the area is 125 square

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Question 374746: I am haveing problems solving this problem I have tried numerous times but i just do not understand it.
A rectangle is 5 times as long as it is wide. If the area is 125 square feet, find its perimiter.
Answer by andsrox(1) About Me  (Show Source):
You can put this solution on YOUR website!
the area of a rectangle = L x W
L = 5W
area = w x 5w
area = 5w%5E2
125 = 5w%5E2
sqrt%28125%29 = sqrt%285w%5E2%29
sqrt%2825%2A5%29 = 5w
5%2Asqrt%285%29 = 5w
%5B5%2Asqrt%285%29+%2F+5 = 5L / 5
sqrt%285%29 = w
L/5 = w
L = 5%2Asqrt%285%29
perimeter = 2W + 2L
p = 2%2Asqrt%285%29 + 2*5*sqrt(5)}}}
p = 2%2Asqrt%285%29 + 10*sqrt(5)}}}
p = 12%2Asqrt%285%29
This was my best guess. Sorry if its wrong.