SOLUTION: The Perimeter of a rectangle is 52 feet. The length and width are represented by two consecutive even integers. Find the dimensions of the rectangle.

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: The Perimeter of a rectangle is 52 feet. The length and width are represented by two consecutive even integers. Find the dimensions of the rectangle.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 368029: The Perimeter of a rectangle is 52 feet. The length and width are represented by two consecutive even integers. Find the dimensions of the rectangle.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Let x & x+2 be the Length & Width.
2L+2W=52
2X+2(X+2)=52
2X+2X+4=52
4X=52-4
4X=48
X=48/4
X=12 ANS. FOR THE LENGTH.
12+2=14 ANS. FOR THE WIDTH.
PROOF:
2*12+2*14=52
24+28=52
52=52