SOLUTION: A wire of length 16 inches is to be cut into two pieces; then each piece will be bent to form a square. Find the length of the two pieces assuming that the sum of the areas of the
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Question 359012: A wire of length 16 inches is to be cut into two pieces; then each piece will be bent to form a square. Find the length of the two pieces assuming that the sum of the areas of the two squares is 10 square inches. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let one piece be x inches
other piece will be 16-x inches
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(x/4)^2+(16-x)/4 ^2=10
x^2/16 +(256-32x+x^2)/16 =10
x^2+256-32x+x^2=160
2x^2-32x+96=0
/2
x^2-16x+48=0
(x-12)(x-4)=0
x=12 OR x=4
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the pieces are 12 & 4 inches
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m.ananth@hotmail.ca
