Question 355063: The area of a rectangular picture is 343.190 square inches. The inside frame is 38.405 by 49.090 inches.How wide is the frame ( same width on all sides)>
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! 38.405*49.090=1,885.3014
(38.405-2x)(49.09-2x)=1,885.3014-343.19
1,885.3014-98.18x-76.81x+4x^2=1,542.1114
4x^2-174.99x+1,885.3014-1,542.1114=0
4x^2-174.99x+343.19=0
x=(174.99+-sqrt[-174.99^2-4*4*343.19])/2*4
x=(174.99+-sqrt[30,621.5-5,491.04])/8
x=(174.99+-sqrt25,130.46)/8
x=(174.99+-158.526)/8
x=(174.99-158.53)/8
x=16.464/8
x=2.06 in. is the width of the mat.
Proof:
(38.405-2*2.06)(49.09-2*2.06)=1,885.3014-343.19
(38.405-4.12)(49.09-4.12)=1,542.1114
34.285*44.97=1,542.1114
1,542~1,542
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