SOLUTION: a ball is placed in a cylindrical can, being tangent to the sides and the bases. the volume of the can is 2008 cm³. find the surface area of the ball.

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Question 354100: a ball is placed in a cylindrical can, being tangent to the sides and the bases. the volume of the can is 2008 cm³. find the surface area of the ball.
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
a ball is placed in a cylindrical can, being tangent to the sides and the bases. the volume of the can is 2008 cm³. find the surface area of the ball.
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Find the radius of the ball.
For the can,
Vol+=+pi%2Ar%5E2%2Ah and h = 2r
V+=+pi%2Ar%5E2%2A2r+=+2pir%5E3
2pi%2Ar%5E3+=+2008
r%5E3+=+1004%2Fpi
r =~ 6.837 cm
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SA+=+4pi%2Ar%5E2
SA = 587.4 sq cm

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
a ball is placed in a cylindrical can, being tangent to the sides and the bases. the volume of the can is 2008 cm³. find the surface area of the ball.
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That can must be a cube.
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Volume = side^3
s^3 = 2008
s = 12.62 cm
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s is also the diameter of the ball.
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radius = s/2 = 6.31 cm
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Surface area of 4(pi)r^2 = 500.34 cm^2
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Cheers,
Stan H.