SOLUTION: If the area of triangle A, with sides of 6, 8, and 10, equals the area of rectangle B, with width of 4, what is the perimeter of the rectangle?

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Question 344676: If the area of triangle A, with sides of 6, 8, and 10, equals the area of rectangle B, with width of 4, what is the perimeter of the rectangle?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Need to know: Heron's formula for computing Area of Triangle knowing the length of its sides a,b,c with s being 1/2 the Perimeter of the Triangle.
Area = sqrt%28s%28s-a%29%28s-b%29%28s-c%29%29
Question states the following to be true: Sides are 6, 8, 10
Perimeter of the triangle is 24
s = 12
substituting gives:
Area = sqrt%2812%2A6%2A4%2A2%29%29
Area = sqrt%28576%29%29
Area = 24
Rectangle B has an equal area with a width of 4
A = w*H
4*H = 24
H = 6
Perimeter of the Rectangle is 2*w + 2*h or in more detail:
4 + 4 + 6 + 6 = 20