SOLUTION: A jet pilot plans to cover a 1000km course at an average speed of 1000 km/h. For the first 800km the speed is 800 km/h. At what rate must the remaining distance be covered?

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Question 338513: A jet pilot plans to cover a 1000km course at an average speed of 1000 km/h. For the first 800km the speed is 800 km/h. At what rate must the remaining distance be covered?
Answer by elissa(1) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: x=2.
  • Graphical form: Equation x%2Bx-x%2B2x=6 was fully solved.
  • Text form: x+x-x+2x=6 simplifies to 0=0
  • Cartoon (animation) form: simplify_cartoon%28+x%2Bx-x%2B2x=6+%29
    For tutors: simplify_cartoon( x+x-x+2x=6 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at .
Eliminated similar terms highlight_red%28+x+%29,highlight_red%28+x+%29,highlight_red%28+-x+%29,highlight_red%28+2%2Ax+%29 replacing them with highlight_green%28+%281%2B1-1%2B2%29%2Ax+%29
It becomes highlight_green%28+%281%2B1-1%2B2%29%2Ax+%29=6.
Look at .
Added fractions or integers together
It becomes %28highlight_green%28+3+%29%29%2Ax=6.
Look at highlight_red%28+%28highlight_red%28+3+%29%29%2Ax+%29=6.
Remove unneeded parentheses around factor highlight_red%28+3+%29
It becomes highlight_green%28+3+%29%2Ax=6.
Look at 3%2Ax=highlight_red%28+6+%29.
Moved these terms to the left highlight_green%28+-6+%29
It becomes 3%2Ax-highlight_green%28+6+%29=0.
Look at highlight_red%28+3%2Ax-6+%29=0.
Solved linear equation highlight_red%28+3%2Ax-6=0+%29 equivalent to 3*x-6 =0
It becomes highlight_green%28+0+%29=0.
Result: 0=0
This is an equation! Solutions: x=2.

Universal Simplifier and Solver


Done!
Solved by pluggable solver: SOLVE a linear equation
Solve 2%2Ax%2B1=5. Move 1 to the right: 2%2Ax=5-1. Divide by 2: x=%285-1%29%2F2=4%2F2+=+2