Question 337157: if the measures of the four interior angles of a pentagon are 112, 102, 118, and 107, what is the measure of the fifth interior angle?
You can put this solution on YOUR website! the sum of the interior angles of an n sided figure is (n-2)*180
This is basically the number of triangles that can be formed inside the figure.
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So a pentagon has n=5 for five sides, and the total of its interior angles =(5-2)*180=540
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the four interior angles given add up to (112+102+118+107)=439
therefore the 5th interior angle is 540-43=101