SOLUTION: the perimeter of a rectangle is 200 inches The length exceeds the width by 50 inches. find the length and the width.
the length is ___ in
the width is ____ in
Algebra ->
Customizable Word Problem Solvers
-> Geometry
-> SOLUTION: the perimeter of a rectangle is 200 inches The length exceeds the width by 50 inches. find the length and the width.
the length is ___ in
the width is ____ in
Log On
Question 330421: the perimeter of a rectangle is 200 inches The length exceeds the width by 50 inches. find the length and the width.
the length is ___ in
the width is ____ in Answer by unlockmath(1688) (Show Source):
You can put this solution on YOUR website! Hello,
Let's have x represent width and x+50 be the length. Now we can set up and equation as:
2x+2(x+50)=200
Combine like terms to get:
4x+100=200
Now subtract 100 and divide by 4 to get:
x=25
So now we know the width is 25 inches and the length is 75 inches.
Make sense?
RJ