SOLUTION: the perimeter of a rectangle is 200 inches The length exceeds the width by 50 inches. find the length and the width. the length is ___ in the width is ____ in

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: the perimeter of a rectangle is 200 inches The length exceeds the width by 50 inches. find the length and the width. the length is ___ in the width is ____ in      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 330421: the perimeter of a rectangle is 200 inches The length exceeds the width by 50 inches. find the length and the width.
the length is ___ in
the width is ____ in

Answer by unlockmath(1688) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
Let's have x represent width and x+50 be the length. Now we can set up and equation as:
2x+2(x+50)=200
Combine like terms to get:
4x+100=200
Now subtract 100 and divide by 4 to get:
x=25
So now we know the width is 25 inches and the length is 75 inches.
Make sense?
RJ