Question 329724: A rectangular building contains 3600 square ft. How many feet are in the perimeter of the lot?
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! This problem has an infinite number of solutions.
Im assuming the building is the same as the lot size.
3,600=xy
Let x=60 & y=60
60*60=3,600
Then the perimeter would be:
2*60+2*60=120+120=240 ft.
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But let x=120 & y=30
120*30=3,600
Now the perimeter is:
2*120+2*30=240+50=290 ft.
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But let x=100 & y=36
100*36=3,6000
Now the perimeter is:
2*100+2*36=200+72=272 ft.
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