SOLUTION: The Width of a rectangular box is twice the height and the length is 4 inches more than the height. if the volume is 48 cubic inches, find the dimensions of the box
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Question 328037: The Width of a rectangular box is twice the height and the length is 4 inches more than the height. if the volume is 48 cubic inches, find the dimensions of the box
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Let x = height
2x= width
x+4 = length
LWH=Volume
x(2x)(x+4)=48
2x^2(x+4)=48
Divide both sides by 2, either now or later. Now is better I think:
x^2(x+4)=24
In order to keep it simple, I would use trial and error, guessing that maybe x=2 would work. It does!!! 2^2(2+4)=24.
x=2 in height
2x=4 in width
x+4=6 in length
Total volume = 2*4*6=48 cubic inches
I don't think I have anything like this on my website, but it does have a LOT of LOT of FREE resources and a GREAT JOKE PAGE--all clean jokes, safe for the little ears in your family!! Click on my tutorname "rapaljer" anywhere in algebra.com. Once you find my Homepage, look for "Joke Page."
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
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