SOLUTION: The perimeter of a rectangle is 600. The length of the rectangle is 2 more than 3 times the width.

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: The perimeter of a rectangle is 600. The length of the rectangle is 2 more than 3 times the width.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 326957: The perimeter of a rectangle is 600. The length of the rectangle is 2 more than 3 times the width.
Answer by jvan(28) About Me  (Show Source):
You can put this solution on YOUR website!
First you should write out the word in equation form. Let l be the length of the rectangle and w be the width of the rectangle =). "The perimeter of a rectangle is 600": 2l%2B2w+=+600. I got this equation from knowing the defintion of perimeter: The perimeter of something is the length of all the sides. Now for the second secntence. "The length of the rectangle is 2 more than 3 times the width.": l=3w%2B2. If you plug l=3w%2B2 into 2l%2B2lw+=+600, you get 2%283w%2B2%29%2B2w+=+600. This becomes 6w%2B4%2B2w+=+600. Adding the w's together and subtracting 4 from both sides you get: 8w+=+596. Divide both sides by 8 to get w=74.5. Then you can plug w=74.5 into equation 2l%2B2w+=+600 or l=3w%2B2 to get the value of l. I'll plug w=74.5 into l=3w%2B2 to get l=3%2874.5%29%2B2. Then solving for l you get l=225.5. So the rectangle is 74.5 by 225.5! ^0^
****--->Please visit my new website at http://myonlinetutor.webs.com and become a member today to get help FREE with 1 problem \(^0^)/! If you tell your friends to become members, you get even more help for FREE (1 FREE problem per friend)!!! ^.^