Question 325212: Can anyone help me figure this out? A tennis ball can in the shape of a right circular cylinder holds three balls snugly, if the radius of a tennis ball is 3.5cm, what percentage of the can is occupied by air?
I know the radius of the ball so I can figure the area of the top and bottom of the cylinder: a = pi r^ so a= 3.14 (3.5)^ = 3.14 x 12.12 = 38.465
I can also figure the area of a sphere for the balls: pi r cubed
3.14(3.5)cubed = 3.14 x 42.875 = 134.6275
for three balls they're taking up 403.8825 space in the can.
I need the height of the can to figure total volume of the can to subtract the amount the balls take up but I'm not sure how to come up with that?
Any help would be appreciated!!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Can anyone help me figure this out? A tennis ball can in the shape of a right circular cylinder holds three balls snugly, if the radius of a tennis ball is 3.5cm, what percentage of the can is occupied by air?
I know the radius of the ball so I can figure the area of the top and bottom of the cylinder: a = pi r^ so a= 3.14 (3.5)^ = 3.14 x 12.12 = 38.465
I can also figure the area of a sphere for the balls: pi r cubed
3.14(3.5)cubed = 3.14 x 42.875 = 134.6275
for three balls they're taking up 403.8825 space in the can.
I need the height of the can to figure total volume of the can to subtract the amount the balls take up but I'm not sure how to come up with that?
Any help would be appreciated!!
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Draw the picture and you will see that the height of the
can is 6(radius of one ball) = 6*3.5 = 21 cm
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Question: Isn't the volume of a sphere (4/3)pi*r^3??
I don't think you want the area of a sprhere which happens to be 4*pi*r^2
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Cheers,
Stan H.
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