SOLUTION: The section that I am on in my class is over contradiction. The equation is Show that neither x=1 or x=-1 can be solutions to the equation ax^2+bx+a=0 where a and b are integers w
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Question 32196: The section that I am on in my class is over contradiction. The equation is Show that neither x=1 or x=-1 can be solutions to the equation ax^2+bx+a=0 where a and b are integers with b odd. Answer by mbarugel(146) (Show Source):
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Try plugging x = 1 into the equation. You get:
However, b is odd, but 2a is even (two multiplied by any number yields an even number). Therefore, x=1 can't be a solution to the equation.
When plugging x = -1, we get:
Using the same reasoning, we conclude that x=-1 can't be a solution of your equation.
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