SOLUTION: find y so that x^2+(y+1)x+y+4=0 has only one solution (i am not asking you to solve the quadratic in terms of y)

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Question 319605: find y so that x^2+(y+1)x+y+4=0 has only one solution (i am not asking you to solve the quadratic in terms of y)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Hint: The quadratic equation ax%5E2%2Bbx%2Bc=0 has only one solution if b%5E2-4ac=0


In this case, a=1, b=y%2B1, and c=y%2B4. Plug this all into the second equation provided above to get %28y%2B1%29%5E2-4%281%29%28y%2B4%29=0. Simply solve this new equation to find the value(s) of 'y' that make x%5E2%2B%28y%2B1%29x%2By%2B4=0 have only one solution.