SOLUTION: I start with a square, increase one side by 3 cm and decrease an adjacent side by 2 cm to form a rectangle of area 24cm2. Find the perimeter of the rectangle (in cm).

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Question 317723: I start with a square, increase one side by 3 cm and decrease an adjacent side by 2 cm to form a rectangle of area 24cm2. Find the perimeter of the rectangle (in cm).
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Start with square of side s.
Go to a rectangle with sides, (s+3) and (s-2)
A=%28s%2B3%29%28s-2%29=24
s%5E2-2s%2B3s-6=24
s%5E2%2Bs-30=0
%28s%2B6%29%28s-5%29=0
Two solutions:
s%2B6=0
s=-6
This solution doesn't make sense in this problem.
.
.
.
s-5=0
s=5
P=s%2B3%2Bs%2B3%2Bs-2%2Bs-2=4s%2B2=4%285%29%2B2
highlight%28P=22%29 cm