SOLUTION: A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 28 square feet, find the lengths of the sides of the poste
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Question 302332: A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 28 square feet, find the lengths of the sides of the poster and the sign? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A square poster has sides measuring 2 feet less than the sides of a square sign.
If the difference between their areas is 28 square feet, find the lengths of the sides of the poster and the sign?
:
Let x = side of the poster
then
(x+2) = side of the sign
:
Sign area - poster area = 28 sq/ft
(x+2)^2 - x^2 = 28
x^2 + 4x + 4 - x^2 = 28
x^2 - x^2 + 4x = 28 - 4
4x = 24
x =
x = 6 ft is the side of the poster
and
6 + 3 = 8 ft is the side of the sign
;
;
Check solution
8^2 - 6^2 =
64 - 36 = 28
